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AP Chemistry Notes

8.11.3 Exam scope for pH–solubility questions

AP Syllabus focus: ‘The AP Exam will not assess calculations of solubility as a function of pH, but qualitative effects of pH changes on solubility are required.’

Understanding what the AP Exam expects for pH and solubility saves time: you must explain directions of change and equilibrium shifts, not compute numerical solubilities or produce pH-dependent solubility curves.

What the AP Exam will and will not ask

In scope: qualitative reasoning only

You are expected to predict whether a solid becomes more soluble or less soluble when pH increases or decreases, and to justify that prediction using equilibrium ideas.

Typical expected reasoning includes:

  • Writing a relevant dissolution equilibrium and identifying the ion affected by pH

  • Explaining how adding H3O+H_3O^+ or OHOH^- changes the amount of an ion via acid–base reaction

  • Applying Le Châtelier’s principle to predict the shift and the solubility trend

Pasted image

These test-tube images show an equilibrium being disturbed by removing an ion from solution via precipitation, causing a shift in the equilibrium position. In pH-dependent solubility problems, the same logic applies when H3O+H_3O^+ consumes OHOH^- (or protonates a basic anion), effectively removing a species and driving dissolution to re-establish equilibrium. Source

  • Stating the final direction clearly (solubility increases/decreases)

Out of scope: calculations linking solubility and pH

You will not be assessed on:

  • Calculating solubility as a function of pH (no deriving ss vs pH relationships)

  • Multi-equation algebra that combines KspK_{sp} with Ka/KbK_a/K_b to compute numerical solubility at a given pH

  • Generating or interpreting quantitative solubility–pH plots beyond simple trend descriptions

Core idea: pH changes the concentration of ions in the KspK_{sp} expression

When pH changes, it can remove or add ions that appear in the dissolution equilibrium (often OHOH^- or a weak acid/base ion), which changes the equilibrium position and therefore the observed solubility.

pH-dependent (pH-sensitive) solubility: when changing pH changes a salt’s solubility because an ion from the salt reacts with H3O+H_3O^+ or OHOH^-, shifting dissolution equilibrium.

A key pattern is that acid consumes basic ions (like OHOH^- or the conjugate bases of weak acids), which tends to increase dissolution to replace the removed ion.

Ksp=[ions]coefficients K_{sp} = \prod [\text{ions}]^{\text{coefficients}}

KspK_{sp} = solubility product constant (unitless in AP convention)

[ions][\text{ions}] = equilibrium ion concentration in mol,L1\text{mol},\text{L}^{-1}

You do not use this equation here to compute solubility changes with pH; you use it to support directional claims (which concentration is reduced by pH change, and which way equilibrium responds).

How to structure an AP-appropriate qualitative justification

A minimal, high-scoring explanation usually includes

  • Identify the relevant ion that is acid/base active:

    • Hydroxides: contain OHOH^-

    • Salts with anions that are conjugate bases of weak acids (e.g., FF^-, CO32CO_3^{2-}, S2S^{2-}): react with H3O+H_3O^+

    • Salts with cations that are conjugate acids of weak bases (e.g., NH4+NH_4^+): can react with OHOH^-

  • State what pH change does chemically:

    • Lower pH means higher H3O+H_3O^+ (more acidic)

    • Higher pH means higher OHOH^- (more basic)

  • Link to equilibrium shifting:

    • If a pH change removes a product ion, dissolution shifts right and solubility increases

    • If a pH change adds a product ion, dissolution shifts left and solubility decreases

Common pH–solubility trend statements (qualitative)

  • For metal hydroxides, lowering pH usually increases solubility because H3O+H_3O^+ removes OHOH^- (driving more solid to dissolve).

  • For salts whose anion is a base (conjugate base of a weak acid), lowering pH often increases solubility because the anion is protonated and removed from solution.

  • If neither ion reacts meaningfully with H3O+H_3O^+ or OHOH^- (ions from strong acids/bases), solubility is often treated as approximately independent of pH on the AP Exam.

FAQ

Check whether the anion is the conjugate base of a weak acid. If its acid form is commonly written as an acid (e.g., $HF$, $H_2CO_3$, $HS^-$), protonation is plausible.

Phrases like “predict”, “justify”, “increases or decreases”, and “explain using equilibrium” signal qualitative expectations, with no request for $K_{sp}$ calculations.

Not necessarily. $K_{sp}$ may be provided to prompt correct equilibrium thinking (which ion is removed/added), even when the required response is only directional.

Focus on the resulting increase in $H_3O^+$ or $OH^-$ (direction of pH change). Treat the buffer as a way to control pH, not as something requiring buffer calculations.

Yes, if the dissolved species includes a cation that is the conjugate acid of a weak base and added acid suppresses a reaction that would otherwise remove it, but AP questions usually emphasise the more common “acid increases solubility” patterns.

Practice Questions

Question 1 (2 marks) A student lowers the pH of a saturated solution of Mg(OH)2(s)Mg(OH)_2(s) by adding HNO3(aq)HNO_3(aq). State and justify the effect on the solubility of Mg(OH)2Mg(OH)_2.

  • Solubility increases (1)

  • Justification: added H3O+H_3O^+ reacts with/removes OHOH^-, shifting dissolution to the right by Le Châtelier (1)

Question 2 (5 marks) Consider two slightly soluble salts: CaF2(s)CaF_2(s) and BaSO4(s)BaSO_4(s). For each salt, predict whether its solubility increases, decreases, or stays approximately the same when the pH is decreased. Justify each prediction with an equilibrium-based argument.

  • CaF2CaF_2: solubility increases (1)

  • Justification: FF^- is protonated by H3O+H_3O^+ to form HFHF, removing FF^- and driving dissolution right (2)

  • BaSO4BaSO_4: solubility stays approximately the same (1)

  • Justification: SO42SO_4^{2-} is the conjugate base of a strong acid in AP context (very weak base), so little reaction with H3O+H_3O^+; no significant shift expected (1)

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