TutorChase logo
Login
AP Chemistry Notes

5.2.4 Rate Constant k: Meaning, Units, and Temperature Dependence

AP Syllabus focus: ‘The proportionality constant k is the rate constant; its value depends on temperature, and its units depend on overall reaction order.’

Kinetics links measured rates to chemical conditions using the rate constant, k. This page explains what k represents, how its units are determined from a rate law, and why temperature changes its value.

Meaning of the rate constant, k

In a rate law, k is the proportionality factor that connects the measured reaction rate to reactant concentrations. For a specific reaction (and a specific mechanism), k is constant only when conditions are fixed, especially temperature.

Rate constant (k): The proportionality constant in a rate law that sets the scale of the reaction rate for given conditions, particularly temperature.

Key interpretation points:

  • A larger k means a faster reaction at the same reactant concentrations.

  • k is not determined from the balanced overall equation alone; it is obtained experimentally from rate data.

  • k does not change when concentrations change during a single run; instead, the rate changes because concentrations appear in the rate law.

  • k can change if conditions change; for AP Chemistry, the most emphasized dependence is temperature.

How k appears in a rate law

A general experimental rate law has the form below; the exponents come from experiment, not stoichiometric coefficients (unless the step is elementary, which is treated elsewhere).

rate=k[A]m[B]p \text{rate} = k[A]^m[B]^p

rate \text{rate} = reaction rate (typically M,s1\mathrm{M,s^{-1}})

k k = rate constant (units depend on overall order)

[A],[B] [A],[B] = molar concentrations, M\mathrm{M}

m,p m,p = experimentally determined reaction orders (unitless)

The overall reaction order is the sum of the concentration exponents in the rate law (here, m + p). This matters because k must supply whatever units are needed so that the right side has the same units as the rate.

Units of k (depend on overall reaction order)

Because rate is commonly reported in M,s1\mathrm{M,s^{-1}}, the units of k depend on the overall order, n. In general:

  • Rate has units M,s1\mathrm{M,s^{-1}}

  • The concentration term has units Mn\mathrm{M^n}

  • Therefore, k must have units that make M,s1=(k)Mn\mathrm{M,s^{-1}} = (k)\mathrm{M^n}

[k]=M,1n,s1 [k] = \mathrm{M^{,1-n},s^{-1}}

[k] [k] = units of the rate constant

n n = overall reaction order (sum of exponents in the rate law)

Common AP Chemistry cases (rate in M,s1\mathrm{M,s^{-1}}):

  • Zero order (n = 0): k has units M,s1\mathrm{M,s^{-1}}

  • First order (n = 1): k has units s1\mathrm{s^{-1}}

  • Second order (n = 2): k has units M1,s1\mathrm{M^{-1},s^{-1}}

  • Third order (n = 3): k has units M2,s1\mathrm{M^{-2},s^{-1}}

Practical notes:

  • Always check the units of the reported rate; if time is in minutes, k will carry min1\mathrm{min^{-1}} (first order) or include min1\mathrm{min^{-1}} with appropriate concentration powers (other orders).

  • Concentration may also be expressed as mol,L1\mathrm{mol,L^{-1}}; M\mathrm{M} and mol,L1\mathrm{mol,L^{-1}} are equivalent.

Temperature dependence of k

The rate constant k is temperature-dependent: increasing temperature typically increases k, often dramatically.

At higher temperature, a greater fraction of collisions (or molecular encounters) have sufficient energy to proceed through the highest-energy point along the pathway, so successful events occur more frequently per unit time.

What to know qualitatively for AP Chemistry:

  • At a higher temperature, k is usually larger, so the reaction is faster even at the same concentrations.

  • The relationship is not linear; modest temperature increases can cause large increases in k.

Pasted image

Arrhenius plot schematic showing that plotting lnk\ln k versus 1/T1/T yields a straight line. The diagram highlights how the slope is calculated and that the slope equals Ea/R-E_a/R, linking temperature sensitivity of kk to activation energy. Source

  • When comparing kinetic data (or k values), temperature must be stated; k values at different temperatures should not be treated as directly comparable without noting that change.

Common pitfalls when using k

  • Treating k as a universal constant: it is constant only for a particular reaction at a particular temperature (and stated conditions).

  • Assuming the balanced equation gives the units of k: the experimental rate law determines n, which determines k’s units.

  • Mixing time units: seconds vs minutes changes the numerical value of k and must be tracked in units.

FAQ

k reflects the specific reaction pathway and energetic barriers.

Different reactants/bond changes lead to different probabilities of successful events per unit time, even if the concentration dependence looks similar.

Only the time unit changes.

For first order: $k(\mathrm{min^{-1}})=60,k(\mathrm{s^{-1}})$. For other orders, the concentration part is unchanged; only the $\mathrm{s^{-1}}$ factor converts.

Because $\mathrm{M}=\mathrm{mol,L^{-1}}$.

So $\mathrm{M^{-1},s^{-1}}=\mathrm{L,mol^{-1},s^{-1}}$; they are equivalent ways to express the same unit.

Not directly.

If temperature and concentrations are the same, k is unchanged; changing volume only matters insofar as it changes concentrations or conditions.

At fixed temperature, k is typically treated as independent of pressure for an elementary ideal-gas description.

However, changing total pressure can change reactant concentrations (via partial pressures), which changes the rate even if k is unchanged.

Practice Questions

(2 marks) For the rate law rate=k[X]2[Y]\text{rate}=k[X]^2[Y], determine the units of kk if rate is measured in mol,L1,s1\mathrm{mol,L^{-1},s^{-1}}.

  • States overall order n=3n=3 (1)

  • Gives [k]=L2,mol2,s1[k]=\mathrm{L^2,mol^{-2},s^{-1}} (or M2,s1\mathrm{M^{-2},s^{-1}}) (1)

(5 marks) A reaction has rate law rate=k[A]\text{rate}=k[A]. In one experiment at constant temperature, doubling [A][A] doubles the rate. In a separate experiment, the temperature is increased while [A][A] is kept the same and the measured rate increases. Explain, using k, why each change affects the rate, and state the units of k.

  • Identifies first-order dependence: rate proportional to [A][A] (1)

  • Explains doubling [A][A] doubles rate because [A][A] is to the first power (1)

  • States k remains constant when only concentration changes (same temperature/conditions) (1)

  • Explains increasing temperature increases k, causing a higher rate at the same [A][A] (1)

  • Gives units of k for first order: s1\mathrm{s^{-1}} (1)

Hire a tutor

Please fill out the form and we'll find a tutor for you.

1/2
Your details
Alternatively contact us via
WhatsApp, Phone Call, or Email